Given a number series and a small value
eps=0.001. With
eps precision (that is, if the sum of the next addition of a term differs by less than
0.001 from the previous one, then this term is considered the last one) find the sum of the series whose common term is given by the formula (
n>0):
\(a_n = {2^n \cdot n! \over{n^n}}\)< /div>
Display the sum of such a series.