The algorithm for calculating the value of the function F(n)
, where n
– natural number, given by the following relations:
F(n) = 5
if n <=
0;
F(n) = F(n / 15) + F(n - 10)
if n
> 0, and the number n
is a multiple of 15;
F(n) = F(n - 3)
if n
> 0, the number n
when divided by 15 is 3;
F(n) = F(n - 1) + n
if n > 0 and n
is not a multiple of 15, and when divided by 15 the remainder is not 3;
What is the minimum value of n
,
for F(n)
to exceed 200
?