The algorithm for calculating the value of the function F(n), where n – natural number, given by the following relations:
F(n) = 3 if n <= 10;
F(n) = F(n / 5) + n if 10 < n <= 200, and the number n is a multiple of 5;
F(n) = F(n - 1) + n if 10 < n <= 200 and n is not a multiple of 5;
F(n) = F(n - 5) if n > 200.
For how many different values n, not exceeding 250, the result F(n) will be equal to 243?